Given the dissociation of methane to graphite (C) and hydrogen gas. For the methane at 298K, Given the following data: kJ = -74.85- mol -80.67 mol · K A,GE.graphite = A, Gắ:9) = 0 %3D Solve the following: a. Calculate the equilibrium constant (K) of the dissociation of methane at 298K with the appropriate units. b. Assuming that enthalpy is independent of temperature, Calculate the equilibrium constant (K) of methane dissociation at 1000 K.

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Given the dissociation of methane to graphite (C) and hydrogen gas. For the methane at 298K,
Given the following data:
kJ
= -74.85-
mol
= -80.67
mol · K
A,GE.graphite
= A,Gån
= 0
%3D
Solve the following:
a. Calculate the equilibrium constant (K) of the dissociation of methane at 298K with the
appropriate units.
b. Assuming that enthalpy is independent of temperature, Calculate the equilibrium constant (K) of
methane dissociation at 1000 K.
C.
Calculate the ratio between the amounts of methane and hydrogen gas at 298 K and 0.2 bar.
Transcribed Image Text:Given the dissociation of methane to graphite (C) and hydrogen gas. For the methane at 298K, Given the following data: kJ = -74.85- mol = -80.67 mol · K A,GE.graphite = A,Gån = 0 %3D Solve the following: a. Calculate the equilibrium constant (K) of the dissociation of methane at 298K with the appropriate units. b. Assuming that enthalpy is independent of temperature, Calculate the equilibrium constant (K) of methane dissociation at 1000 K. C. Calculate the ratio between the amounts of methane and hydrogen gas at 298 K and 0.2 bar.
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