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Given the diagram below, if J is the incenter of ADEF, MZDEJ=(6x+1)° and MZJEF=(10x-23)°, find mZFDJ. Round answers to the nearest tenth when needed. E H G 25° D I F MZFDJ=

Given the diagram below, if J is the incenter of ADEF, MZDEJ=(6x+1)° and MZJEF=(10x-23)°, find mZFDJ. Round answers to the nearest tenth when needed. E H G 25° D I F MZFDJ=

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Given the diagram below, if \( J \) is the incenter of \(\triangle DEF\), \( m\angle DEJ = (6x+1)^\circ \) and \( m\angle JEF = (10x-23)^\circ \), find \( m\angle FDJ \). Round answers to the nearest tenth when needed. Diagram: - Triangle \( \triangle DEF \) is shown with \( J \) as the incenter. - Line segments \( EJ, DJ, \) and \( FJ \) are shown intersecting at point \( J \). - The diagram indicates that: - \( m\angle EIF = 25^\circ \) - \( G, H, \) and \( I \) are points on \( DE, EF, \) and \( FD \) respectively, forming right angles with the sides of the triangle, indicating perpendicular bisectors meeting at the incenter \( J \). To find: \( m\angle FDJ = \boxed{ }\)
Transcribed Image Text:Given the diagram below, if \( J \) is the incenter of \(\triangle DEF\), \( m\angle DEJ = (6x+1)^\circ \) and \( m\angle JEF = (10x-23)^\circ \), find \( m\angle FDJ \). Round answers to the nearest tenth when needed. Diagram: - Triangle \( \triangle DEF \) is shown with \( J \) as the incenter. - Line segments \( EJ, DJ, \) and \( FJ \) are shown intersecting at point \( J \). - The diagram indicates that: - \( m\angle EIF = 25^\circ \) - \( G, H, \) and \( I \) are points on \( DE, EF, \) and \( FD \) respectively, forming right angles with the sides of the triangle, indicating perpendicular bisectors meeting at the incenter \( J \). To find: \( m\angle FDJ = \boxed{ }\)
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