Given the curve y² = 5x – 1 at point ( 1,-2 ) , find the equation of tangent and normal to the curve. A. 5x + 4y + 3 = 0 & 4x- 5y- 14 = 0 B. 5x + 4y-3 = 0 & 4x + 5y- 14 = 0 C. 5x- 4y +3= 0 & 4x + 5y + 14 0 D. 5x- 4y-3 = 0 & 4x + 5y – 14 = 0 ズI

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the curve y? = 5x – 1 at point ( 1,-2 ) , find the equation of tangent and normal to
the curve.
A. 5x + 4y + 3 = 0 & 4x - 5y- 14 = 0
B. 5x + 4y-3 = 0 & 4x + 5y - 14 = 0
C. 5x- 4y +3= 0 & 4x + 5y + 14 = 0
D. 5x – 4y- 3 = 0 & 4x + 5y – 14 = 0
Transcribed Image Text:Given the curve y? = 5x – 1 at point ( 1,-2 ) , find the equation of tangent and normal to the curve. A. 5x + 4y + 3 = 0 & 4x - 5y- 14 = 0 B. 5x + 4y-3 = 0 & 4x + 5y - 14 = 0 C. 5x- 4y +3= 0 & 4x + 5y + 14 = 0 D. 5x – 4y- 3 = 0 & 4x + 5y – 14 = 0
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