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Given the compound curve with the vertex V inaccessible, angles A and B are equal to 16°20' and 13°30', respectively. Stationing at B is at 1+125. 92m. Degrees of curve are 3°30' and 4°00' for the first and second curve, respectively. It is desired to substitute the compound curve with a simple curve that shall be tangent to the two tangents, T₁ and TB, and as well as the common tangent TAB. Determine the radius of the simple curve Solution: 1+125.92m P.CO of LC₁ 16°20' 0₂ R₂ 13°30 LC₂ B P.T

Given the compound curve with the vertex V inaccessible, angles A and B are equal to 16°20' and 13°30', respectively. Stationing at B is at 1+125. 92m. Degrees of curve are 3°30' and 4°00' for the first and second curve, respectively. It is desired to substitute the compound curve with a simple curve that shall be tangent to the two tangents, T₁ and TB, and as well as the common tangent TAB. Determine the radius of the simple curve Solution: 1+125.92m P.CO of LC₁ 16°20' 0₂ R₂ 13°30 LC₂ B P.T

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Given the compound curve with the vertex V inaccessible, angles A and B are equal to 16°20' and 13°30', respectively. Stationing at B is at 1+125. 92m. Degrees of curve are 3°30' and 4°00' for the first and second curve, respectively. It is desired to substitute the compound curve with a simple curve that shall be tangent to the two tangents, T₁ and TB, and as well as the common tangent TAB. Determine the radius of the simple curve Solution: 1+125.92m P.CO of LC₁ 16°20' 0₂ R₂ 13°30 LC₂ B P.T
Transcribed Image Text:Given the compound curve with the vertex V inaccessible, angles A and B are equal to 16°20' and 13°30', respectively. Stationing at B is at 1+125. 92m. Degrees of curve are 3°30' and 4°00' for the first and second curve, respectively. It is desired to substitute the compound curve with a simple curve that shall be tangent to the two tangents, T₁ and TB, and as well as the common tangent TAB. Determine the radius of the simple curve Solution: 1+125.92m P.CO of LC₁ 16°20' 0₂ R₂ 13°30 LC₂ B P.T
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