Given the code below, what is ARR[4]?    int ARR[10];    ARR[0] = 1;    ARR[1] = 2;    for (int i = 2; i < 10; i++)    {       if ( (I % 2) == 1 )          ARR[I] = ARR[I-1] + ARR[I-2];       else          ARR[I] := 2 * ARR[I-1];    }

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A: Please find the solution below

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A: The program is to double the even elements in an array.

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A: Output :-

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A:

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A: The program is written in Java. Please find the source code below.

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A: Answer in step 2

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A: T/F Question. Suffix array can be created in O(nlogn) time.

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A: Refer to step 2 for the answer.

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A: Code :

Q: s[0]=7;s[1]=0;s[2]=-12;s[3]=9;s[4]=10;s[5]=3;s[6]=6; the value of [s[6-s[5]]is:

A: s[6-s[5]] = 9