Given the circuit in figure 5 (vc (0) = 1V and i₁(0) = 0.3A:Transform the circuit to the Laplace domainFind the IR (S) which is the Laplace transform of current ik (t)C=ImFR = 500-2●●is(t) aGiven:●●|Us(t) = 4 exp(-St)u(t)v₁ (0) = IV(0) 0.3Avs (t) = 4e-5tu(t)VR=5000L=1HC=1mFvc (0) = 1ViL (0) = 0.3AFigure 53L=1H

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Given the circuit in figure 5 (vc(0) = 1V and i, (0) = 0.3A: Transform the circuit to the Laplace domain Find the IR (S) which is the Laplace transform of current i, (t) C=1mF R = 500-2 ● ● is(t). A Given: ● ● ● ● ● √5 (t) = 4 exp(-St)u(t) &(0) = 1 iL (0) = 0.3 A vs(t) = 4e-stu(t)V R=5000 L=1H C=1mF vc (0) = 1V il (0)= 0.3A Figure 5 3L=1H

Given the circuit in figure 5 (vc(0) = 1V and i, (0) = 0.3A: Transform the circuit to the Laplace domain Find the IR (S) which is the Laplace transform of current i, (t) C=1mF R = 500-2 ● ● is(t). A Given: ● ● ● ● ● √5 (t) = 4 exp(-St)u(t) &(0) = 1 iL (0) = 0.3 A vs(t) = 4e-stu(t)V R=5000 L=1H C=1mF vc (0) = 1V il (0)= 0.3A Figure 5 3L=1H

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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