Given the building layout for Store A, Store B, Store C, and Store D, what portion of the shared $7500 maintenance costs should be apportioned to Store A? A B C D 625 ft² 625 ft² 2500ft² 2500ft² apportioned cost = $ [?] Round you answer to the nearest hundredth. Enter
Given the building layout for Store A, Store B, Store C, and Store D, what portion of the shared $7500 maintenance costs should be apportioned to Store A? A B C D 625 ft² 625 ft² 2500ft² 2500ft² apportioned cost = $ [?] Round you answer to the nearest hundredth. Enter
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![**Apportioning Maintenance Costs Based on Store Layout**
**Problem Statement:**
Given the building layout for Store A, Store B, Store C, and Store D, what portion of the shared $7500 maintenance costs should be apportioned to Store A?
**Building Layout:**
- Store A: 2500 ft²
- Store B: 625 ft²
- Store C: 625 ft²
- Store D: 2500 ft²
**Diagram:**
A visual representation of the layout is shown below with the respective floor areas.
```
-----------------------------------------------------
| | B | C | |
| A |625|625| D |
| 2500 ft² | ft²| ft²| 2500 ft² |
-----------------------------------------------------
```
**Task:**
Calculate the apportioned maintenance cost for Store A based on its floor area compared to the total area of all stores.
**Calculation:**
The total floor area for all stores combined is:
2500 ft² (A) + 625 ft² (B) + 625 ft² (C) + 2500 ft² (D) = 6250 ft²
**Proportion Calculation:**
\[ \text{Proportion of Store A} = \frac{\text{Store A's area}}{\text{Total area}} = \frac{2500}{6250} = 0.4 \]
**Apportioned Cost:**
\[ \text{Apportioned cost for Store A} = \text{Proportion of Store A} \times \text{Total maintenance costs} \]
\[ = 0.4 \times 7500 = \$3000 \]
**Answer:**
The apportioned maintenance cost for Store A is $3000.
**Note:** Round your answer to the nearest hundredth where necessary.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0ca0459b-7c1d-4bc5-a010-9c0fc83c1378%2F1bcfec96-d312-4c45-b22c-8ca887d3a071%2Fkp8ume_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Apportioning Maintenance Costs Based on Store Layout**
**Problem Statement:**
Given the building layout for Store A, Store B, Store C, and Store D, what portion of the shared $7500 maintenance costs should be apportioned to Store A?
**Building Layout:**
- Store A: 2500 ft²
- Store B: 625 ft²
- Store C: 625 ft²
- Store D: 2500 ft²
**Diagram:**
A visual representation of the layout is shown below with the respective floor areas.
```
-----------------------------------------------------
| | B | C | |
| A |625|625| D |
| 2500 ft² | ft²| ft²| 2500 ft² |
-----------------------------------------------------
```
**Task:**
Calculate the apportioned maintenance cost for Store A based on its floor area compared to the total area of all stores.
**Calculation:**
The total floor area for all stores combined is:
2500 ft² (A) + 625 ft² (B) + 625 ft² (C) + 2500 ft² (D) = 6250 ft²
**Proportion Calculation:**
\[ \text{Proportion of Store A} = \frac{\text{Store A's area}}{\text{Total area}} = \frac{2500}{6250} = 0.4 \]
**Apportioned Cost:**
\[ \text{Apportioned cost for Store A} = \text{Proportion of Store A} \times \text{Total maintenance costs} \]
\[ = 0.4 \times 7500 = \$3000 \]
**Answer:**
The apportioned maintenance cost for Store A is $3000.
**Note:** Round your answer to the nearest hundredth where necessary.
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