Given the B-sided figure below with exterior angle measures as shown, what is the value of X? 75° 68% A B C D 15 x=148 x=125" x=55* x= 105⁰ 32⁰ 28% 201

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
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Chapter10: Measurement, Area, And Volume
Section10.1: Triangles
Problem 1C
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**Problem Statement:**

Given the 8-sided figure below with exterior angle measures as shown, what is the value of \( x \)?

**Diagram:**

In the diagram, an 8-sided irregular polygon is presented with the following exterior angles labeled (clockwise from the top as seen in the provided figure):

- \( 68^\circ \)
- \( 75^\circ \)
- \( x \)
- \( 67^\circ \)
- \( 20^\circ \)
- \( 28^\circ \)
- \( 32^\circ \)
- \( 15^\circ \)

**Answer Choices:**
A) \( x = 148^\circ \)

B) \( x = 125^\circ \)

C) \( x = 55^\circ \)

D) \( x = 105^\circ \)

**Solution:**

To determine the value of \( x \), recall that the sum of all exterior angles of any polygon is always \( 360^\circ \).

Sum of given exterior angles + \( x \) = \( 360^\circ \)

So,

\( 68 + 75 + x + 67 + 20 + 28 + 32 + 15 = 360 \)

Calculating the sum of the known exterior angles:

\( 68 + 75 + 67 + 20 + 28 + 32 + 15 = 305 \)

Now, solve for \( x \):

\( 305 + x = 360 \)

\( x = 360 - 305 \)

\( x = 55 \)

**Correct Answer:**

C) \( x = 55^\circ \)
Transcribed Image Text:**Problem Statement:** Given the 8-sided figure below with exterior angle measures as shown, what is the value of \( x \)? **Diagram:** In the diagram, an 8-sided irregular polygon is presented with the following exterior angles labeled (clockwise from the top as seen in the provided figure): - \( 68^\circ \) - \( 75^\circ \) - \( x \) - \( 67^\circ \) - \( 20^\circ \) - \( 28^\circ \) - \( 32^\circ \) - \( 15^\circ \) **Answer Choices:** A) \( x = 148^\circ \) B) \( x = 125^\circ \) C) \( x = 55^\circ \) D) \( x = 105^\circ \) **Solution:** To determine the value of \( x \), recall that the sum of all exterior angles of any polygon is always \( 360^\circ \). Sum of given exterior angles + \( x \) = \( 360^\circ \) So, \( 68 + 75 + x + 67 + 20 + 28 + 32 + 15 = 360 \) Calculating the sum of the known exterior angles: \( 68 + 75 + 67 + 20 + 28 + 32 + 15 = 305 \) Now, solve for \( x \): \( 305 + x = 360 \) \( x = 360 - 305 \) \( x = 55 \) **Correct Answer:** C) \( x = 55^\circ \)
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