Given the arrangement of charged particles in the figure below, find the net electrostatic force on the q1 = 5.55-µc charged particle. (Assume q2 = 16.33 µC and q3 = -17.12 µC. Express your answer in vector form.)
Given the arrangement of charged particles in the figure below, find the net electrostatic force on the q1 = 5.55-µc charged particle. (Assume q2 = 16.33 µC and q3 = -17.12 µC. Express your answer in vector form.)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Can you PLEASE SHOW ME WHERE I WENT WRONG IN THIS PROBLEM?
PLEASE SHOW ME HOW TO DECOMPOSE THE VECTORS FOR THIS PROBLEM!! PLEASE!!!
PLEASE DO NOT SKIP ANY STEPS PLEASE MAKE SURE TO DOUBLE CHECK YOUR WORK AND PLEASE SHOW ME HOW TO DECOMPOSE THESE FORCE VECTORS TO SOLVE THIS PROBLEM!!
PLEASE DOUBLE CHECK YOUR WORK.
Transcribed Image Text:estion 6.
Given the arrangement of charged particles in the figure below, find the net electrostatic force on the q =5.55-uC charged
particle. (Assume q2 = 16.33 µC and q3 = -17.12 µc. Express your answer in vector form.)
IpC = 10*C Q= S.5se-bC
5.5uC-6,55e6 Q = 1,63)E-5
N
%3D
1000 000
B,
(1.00 cm, 1.00 em
Qz = -1.712 E-5
Subjeut
4.
A,
3.le-Zn
= -0.02 m
01
1200 cm, Da
A,
B, = 0.01m
k= 8.99169
%3D
(0, -1.00 cm)
Cy'e -0.이m
(7.04228
Subjeut)
Do tane blin AtB = 31le-2m
V
3.1le-2m
- ,02- .01)² + CO- .01)²
Do tance brun A tc = 2.24e-2M
V(-.02 - 0)² +(0 - (- .01))*
%3D
All the forces on q, are
on I
Cos B= Cos a
Sin d if
VTO
2on I
8.16e2
%3D
(3.1be-2) ²
F2on= kl-1.712 e-5* 5.5te-6|
(2.244e-2)2
1,70€3
3on 1
6
Transcribed Image Text:Given the arrangement of charged particles in the figure below, find the net electrostatic force on the q1 = 5.55-µc charged
particle. (Assume q2 = 16.33 µC and q3 = -17.12 µC. Express your answer in vector form.)
y
|(1.00 cm, 1.00 cm)
92
(-2,00 cm, 0)
(0, — 1.00 сm)
93
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