Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals). a. P(-1.98 < z< 0.49) b. P(0.58
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Q: places. (a) P(Z s -0.95) = [| (b) P(Z > -1.24) (c) P(0.58 < Z < 1.83) = |
A: See the handwritten solution
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Q: a. P(zszo) = 0.0605 b. P(-Zo Szszo) = 0.99 c. P(-Zo Szszo) = 0.95
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A: P(−1.98<z< - 0.03) = P(Z< -0.03) – P(Z< -1.98) = 0.488034 – 0.023852 = 0.464182 P(Z <…
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Q: to four decimal places as needed.) e) P( − 1.1 ≤Z≤1.7) =| Round to four decimal places as needed.)
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A: From excel: Thus, Z0 = 1.50
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Q: Let Z be a standard normal random variable. Calculate the following probabilities using the ALEKS…
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- Let Z be a standard normal random variable, Calculate the following probabilities using the ALEKS calculator. Round your responses to at least three decimal places. (a) P(Z S 1.77) = O (b) P(Z > 1.72) = 0 (c) P(-0.67 < z < 2.20) = |Let Z be a standard normal random variable. Calculate the following probabilities using the calculator provided. Round your responses to at least three decimal places. P(z > -0.66) = 0 P(Z s 2.13) = 0 P(-0.38 < Z < 2.10) = 0The random sample X is normally distributed with mean 50 and standard deviation 18. If n=324, compute the following probabilities: P(X 2 48) is: O.5080 .4772 .9772 .6038 O O O O
- The accompanying table describes results from groups of 10 births from 10 different sets of parents. The random variable x represents the number of girls among 10 children. Use the range rule of thumb to determine whether 1 girl in 10 births is a significantly low number of girls. x P(x)0 0.0041 0.0132 0.0363 0.1154 0.2065 0.2386 0.2017 0.1168 0.0459 0.01310 0.013 The maximum value in this range is __ girls. (round to one decimal places as needed) The minimum value in this range is __ girls. (round to one decimal place as needed) Based on the result, is 1 girl in 10 births a significantly low number of girls? Explain. A. No, 1 girl is not a significantly low number of girls, because 1 girl is within the range of values that are not significant. B. Yes, 1 girl is a significantly low number of girls, because 1 girl is below the range of values that are not significant. C. Yes, 1 girl is a significantly low number of girls, because 1 girl is above the…Let x be a normally distributed random variable with the following parameters: μ = 135.628 σ = 28.622 12 What is the probability that x will be below 100 ? a 0.1343 b 0.1243 c 0.1151 d 0.1066Find the following probability for the standard normal random variable z. a. P(z=2) e. P(-2≤z≤2) b. P(z ≤2) f. P(-1≤z≤1) c. P(Z 2) h. P(-0.35Let Z be a standard normal random variable. Calculate the following probabilities using the calculator provided. Round your responses to at least three decimal places. P(z > 1.53) = |Let Z be a standard normal random variable. Calculate the following probabilities using the calculator provided. Round your responses to at least three decimal places. P(z s 0.52) = 0 P(z > -1.60) = 0 P(0.78 < z < 2.17) = OIf x is a binomial random variable, use the binomial probability table to find the probabilities below. a. P(x < 7) for n = 15, p = 0.8 b. P(x ≥ 13) for n = 20, p = 0.3 c. P(x = 2) for n = 25, p = 0.5If z is a standard normal random variable, then P (1.83 < z < 2.38) is:Let Z be a standard normal random variable. Calculate the following probabilities using the ALEKS calculator. Round your responses to at least three decimal places. (a) P(Z s 0.68) = [D (b) P(z > -1.90) = (c) P(1.10 < Z < 2.20) =