Given that y₁ (t) = cost is a solution to y'' -y' + y = sint and y₂ (t)=3 is a solution to y'' - y' + y = e²t, use the superposition principle to find solutions to the differential equations in parts (a) through (c) below. (a) y'-y'+y=12 sin t A solution is y(t) = (b) y'-y'+y=3 sint-6 e 2t A solution is y(t) =
Given that y₁ (t) = cost is a solution to y'' -y' + y = sint and y₂ (t)=3 is a solution to y'' - y' + y = e²t, use the superposition principle to find solutions to the differential equations in parts (a) through (c) below. (a) y'-y'+y=12 sin t A solution is y(t) = (b) y'-y'+y=3 sint-6 e 2t A solution is y(t) =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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part a and b
![Given that \( y_1(t) = \cos t \) is a solution to \( y'' - y' + y = \sin t \) and \( y_2(t) = \frac{e^{2t}}{3} \) is a solution to \( y'' - y' + y = e^{2t} \), use the superposition principle to find solutions to the differential equations in parts (a) through (c) below.
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**(a)** \( y'' - y' + y = 12 \sin t \)
A solution is \( y(t) = \boxed{\phantom{y(t)}} \).
**(b)** \( y'' - y' + y = 3 \sin t - 6 e^{2t} \)
A solution is \( y(t) = \boxed{\phantom{y(t)}} \).
**(c)** \( y'' - y' + y = 5 \sin t + 15 e^{2t} \)
A solution is \( y(t) = \boxed{\phantom{y(t)}} \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa827acfe-a0bc-46c0-ab61-62657df3b5db%2F07b63729-5958-46da-a9a5-b80adedd87b3%2Fsilm7jr_processed.png&w=3840&q=75)
Transcribed Image Text:Given that \( y_1(t) = \cos t \) is a solution to \( y'' - y' + y = \sin t \) and \( y_2(t) = \frac{e^{2t}}{3} \) is a solution to \( y'' - y' + y = e^{2t} \), use the superposition principle to find solutions to the differential equations in parts (a) through (c) below.
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**(a)** \( y'' - y' + y = 12 \sin t \)
A solution is \( y(t) = \boxed{\phantom{y(t)}} \).
**(b)** \( y'' - y' + y = 3 \sin t - 6 e^{2t} \)
A solution is \( y(t) = \boxed{\phantom{y(t)}} \).
**(c)** \( y'' - y' + y = 5 \sin t + 15 e^{2t} \)
A solution is \( y(t) = \boxed{\phantom{y(t)}} \).
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