Given that x..= 22 Xij = 596 and 2x = 29986 calculate the following The correction factor, CF = The first-row sum: x1. = E; X1j = The second-row sum: x2, = E; x2j = The third-row sum: x3, = Lj X3j = The fourth-row sum: x4, = Ej x4j = The first-column sum: x,1 =£j Xi1 = The second-column sum: x2 = Ej Xi2 = i) ii) iii) iv) %3D %3D v) %3D vi) vii) %3D %3D

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