Given that x and y show inverse variation, complete the table. 3 27 27 9

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### Inverse Variation: Completing the Table

Given that \( x \) and \( y \) show inverse variation, complete the table.

\[
\begin{array}{|c|c|c|c|c|}
\hline
x & 1 & 3 & \_ & 27 \\
\hline
y & \_ & \_ & 9 & \_ \\
\hline
\end{array}
\]

Inverse variation means that the product of \( x \) and \( y \) is constant. That is, \( x \times y = k \) for some constant \( k \).

To complete the table, first determine the constant \( k \) using the given pairs:
- For \( x = 1 \) and \( y = 27 \):
  \[
  1 \times 27 = 27 \implies k = 27
  \]

Now use \( k = 27 \) to find the missing values.

1. When \( x = 3 \):
   \[
   x \times y = 27 \implies 3 \times y = 27 \implies y = \frac{27}{3} = 9
   \]

2. When \( y = 9 \):
   \[
   x \times 9 = 27 \implies x = \frac{27}{9} = 3
   \]

3. When \( x = 27 \):
   \[
   x \times y = 27 \implies 27 \times y = 27 \implies y = \frac{27}{27} = 1
   \]

Now, fill in the table with the calculated values:

\[
\begin{array}{|c|c|c|c|c|}
\hline
x & 1 & 3 & 9 & 27 \\
\hline
y & 27 & 9 & 3 & 1 \\
\hline
\end{array}
\]

This table demonstrates the principle of inverse variation between \( x \) and \( y \).
Transcribed Image Text:### Inverse Variation: Completing the Table Given that \( x \) and \( y \) show inverse variation, complete the table. \[ \begin{array}{|c|c|c|c|c|} \hline x & 1 & 3 & \_ & 27 \\ \hline y & \_ & \_ & 9 & \_ \\ \hline \end{array} \] Inverse variation means that the product of \( x \) and \( y \) is constant. That is, \( x \times y = k \) for some constant \( k \). To complete the table, first determine the constant \( k \) using the given pairs: - For \( x = 1 \) and \( y = 27 \): \[ 1 \times 27 = 27 \implies k = 27 \] Now use \( k = 27 \) to find the missing values. 1. When \( x = 3 \): \[ x \times y = 27 \implies 3 \times y = 27 \implies y = \frac{27}{3} = 9 \] 2. When \( y = 9 \): \[ x \times 9 = 27 \implies x = \frac{27}{9} = 3 \] 3. When \( x = 27 \): \[ x \times y = 27 \implies 27 \times y = 27 \implies y = \frac{27}{27} = 1 \] Now, fill in the table with the calculated values: \[ \begin{array}{|c|c|c|c|c|} \hline x & 1 & 3 & 9 & 27 \\ \hline y & 27 & 9 & 3 & 1 \\ \hline \end{array} \] This table demonstrates the principle of inverse variation between \( x \) and \( y \).
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