Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 61E
Related questions
Question
5
![Refer to the table below if needed.
Second Quadrant
Third Quadrant
Fourth Quadrant
sin(180° -e) = sine
sin(180. +e) = - sine
sin(360° -e) = - sine
cos(180° -e) = - cose
cos(180° +e) = - cose
cos(360° -e) = cose
%3D
tan(1800 -e) = - tane
tan(1800 +e) = tane
tan(360. -e) = - tane
cot(1800 -e) = - cote
cot(180° +e) = cote
cot(360. -e) = - cote
sec(180° -e) = - sece
sec(180° +e) = - sece
sec(360° -e) = sece
csc(180° -e) = csce
csc(1800 +e) = - cSCe
csc(360° -e) = - csce
Given that sine = 4/5 and e lies in quadrant II, find the following value.
csce
5/4
4/5
5/3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5f7b3938-790b-4169-a858-04369df79473%2F93ca360d-dc75-4ac7-b459-94cab42ff868%2Fjq5fdzs_processed.png&w=3840&q=75)
Transcribed Image Text:Refer to the table below if needed.
Second Quadrant
Third Quadrant
Fourth Quadrant
sin(180° -e) = sine
sin(180. +e) = - sine
sin(360° -e) = - sine
cos(180° -e) = - cose
cos(180° +e) = - cose
cos(360° -e) = cose
%3D
tan(1800 -e) = - tane
tan(1800 +e) = tane
tan(360. -e) = - tane
cot(1800 -e) = - cote
cot(180° +e) = cote
cot(360. -e) = - cote
sec(180° -e) = - sece
sec(180° +e) = - sece
sec(360° -e) = sece
csc(180° -e) = csce
csc(1800 +e) = - cSCe
csc(360° -e) = - csce
Given that sine = 4/5 and e lies in quadrant II, find the following value.
csce
5/4
4/5
5/3
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