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Given that sine = -1/2 and e lies in quadrant IV, find the following value. cose -2

Given that sine = -1/2 and e lies in quadrant IV, find the following value. cose -2

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Refer to the table below if needed. Second Quadrant Third Quadrant Fourth Quadrant sin(1800 -e) = sine sin(180• +e) = - sing sin(360° -e) = - sing cos(180° -e) = - cose cos(1800 +e) = - cose cos(360° -e) = cose tan(1800 -e) = - tane tan(180° +e) = tane tan(360° -e) = - tane cot(180° -e) = - cote cot(1800 +e) = cote cot(360° -e) = - cote sec(180° -e) = - sece sec(180° +e) = - sece sec(360° -e) = sece csc(180° -e) = csce csc(1800 +e) = - cSce csc(360° -e) = - CSCA Given that sine = -1/2 and e lies in quadrant IV, find the following value. cose -2 -V3/2 V3/2
Transcribed Image Text:Refer to the table below if needed. Second Quadrant Third Quadrant Fourth Quadrant sin(1800 -e) = sine sin(180• +e) = - sing sin(360° -e) = - sing cos(180° -e) = - cose cos(1800 +e) = - cose cos(360° -e) = cose tan(1800 -e) = - tane tan(180° +e) = tane tan(360° -e) = - tane cot(180° -e) = - cote cot(1800 +e) = cote cot(360° -e) = - cote sec(180° -e) = - sece sec(180° +e) = - sece sec(360° -e) = sece csc(180° -e) = csce csc(1800 +e) = - cSce csc(360° -e) = - CSCA Given that sine = -1/2 and e lies in quadrant IV, find the following value. cose -2 -V3/2 V3/2
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