Given that P(A)=3, P(B)=, and P(A and B)=10, find P(A or B). 7 ㅇ 10 45 3/10 5 34

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**Question:**

Given that P(A) = \( \frac{3}{5} \), P(B) = \( \frac{1}{5} \), and P(A and B) = \( \frac{1}{10} \), find P(A or B).

**Options:**

1. \( \frac{7}{10} \) 
2. \( \frac{4}{5} \) 
3. \( \frac{3}{5} \) 
4. \( \frac{3}{4} \) 

**Solution:**

To find P(A or B), we use the formula for the probability of the union of two events:

\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]

Given:

- P(A) = \( \frac{3}{5} \) 
- P(B) = \( \frac{1}{5} \) 
- P(A and B) = \( \frac{1}{10} \)

Substitute the values into the formula:

\[ P(A \cup B) = \frac{3}{5} + \frac{1}{5} - \frac{1}{10} \]

Convert the fractions to a common denominator to simplify the calculation. The common denominator for 5 and 10 is 10:

\[ \frac{3}{5} = \frac{6}{10} \]
\[ \frac{1}{5} = \frac{2}{10} \]

Now substitute these into the formula:

\[ P(A \cup B) = \frac{6}{10} + \frac{2}{10} - \frac{1}{10} \]

Combine the fractions:

\[ P(A \cup B) = \frac{6 + 2 - 1}{10} = \frac{7}{10} \]

So the probability P(A or B) is:

\[ \boxed{\frac{7}{10}} \]

In the provided options, the correct answer should be selected. 

Therefore, the correct answer should be \( \frac{7}{10} \), however, noting that the second option \( \frac{4}{5} \) is marked, the proper understanding and selection process should have identified \( \frac{7}{10} \). Therefore, there is a marked discrepancy to be corrected and the right answer is indeed \( \frac
Transcribed Image Text:**Question:** Given that P(A) = \( \frac{3}{5} \), P(B) = \( \frac{1}{5} \), and P(A and B) = \( \frac{1}{10} \), find P(A or B). **Options:** 1. \( \frac{7}{10} \) 2. \( \frac{4}{5} \) 3. \( \frac{3}{5} \) 4. \( \frac{3}{4} \) **Solution:** To find P(A or B), we use the formula for the probability of the union of two events: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] Given: - P(A) = \( \frac{3}{5} \) - P(B) = \( \frac{1}{5} \) - P(A and B) = \( \frac{1}{10} \) Substitute the values into the formula: \[ P(A \cup B) = \frac{3}{5} + \frac{1}{5} - \frac{1}{10} \] Convert the fractions to a common denominator to simplify the calculation. The common denominator for 5 and 10 is 10: \[ \frac{3}{5} = \frac{6}{10} \] \[ \frac{1}{5} = \frac{2}{10} \] Now substitute these into the formula: \[ P(A \cup B) = \frac{6}{10} + \frac{2}{10} - \frac{1}{10} \] Combine the fractions: \[ P(A \cup B) = \frac{6 + 2 - 1}{10} = \frac{7}{10} \] So the probability P(A or B) is: \[ \boxed{\frac{7}{10}} \] In the provided options, the correct answer should be selected. Therefore, the correct answer should be \( \frac{7}{10} \), however, noting that the second option \( \frac{4}{5} \) is marked, the proper understanding and selection process should have identified \( \frac{7}{10} \). Therefore, there is a marked discrepancy to be corrected and the right answer is indeed \( \frac
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