Given that: M = îo – Ôtane 1-Transform this vector into Cartesian coordinates? 2- Find the divergence of this vector in Cartesian coordinates?

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### Question
Given that:
\[ \vec{M} = \hat{r_0} - \hat{\theta} \tan{\theta} \]

1. Transform this vector into Cartesian coordinates.
2. Find the divergence of this vector in Cartesian coordinates.

### Explanations

1. **Transforming Vector into Cartesian Coordinates**:
   To transform \( \vec{M} \) from polar coordinates (\( \hat{r_0} \) and \( \hat{\theta} \)) to Cartesian coordinates (\( \hat{i} \) and \( \hat{j} \)), we need to use the relationships between polar and Cartesian unit vectors:

   - \( \hat{r_0} = \cos{\theta} \hat{i} + \sin{\theta} \hat{j} \)
   - \( \hat{\theta} = -\sin{\theta} \hat{i} + \cos{\theta} \hat{j} \)

   Substitute these into the given vector equation:
   \[ \vec{M} = (\cos{\theta} \hat{i} + \sin{\theta} \hat{j}) - \tan{\theta} (-\sin{\theta} \hat{i} + \cos{\theta} \hat{j}) \]
   Simplify this expression to get \( \vec{M} \) in terms of \( \hat{i} \) and \( \hat{j} \).

2. **Finding the Divergence**:
   Once \( \vec{M} \) is expressed in Cartesian coordinates, apply the divergence operator, \( \nabla \cdot \vec{M} \), which in Cartesian coordinates is:
   \[ \nabla \cdot \vec{M} = \frac{\partial M_x}{\partial x} + \frac{\partial M_y}{\partial y} \]
   where \( M_x \) and \( M_y \) are the components of \( \vec{M} \) in the \( \hat{i} \) and \( \hat{j} \) directions respectively.

These steps will help in transforming the vector and then finding its divergence in Cartesian coordinates.
Transcribed Image Text:### Question Given that: \[ \vec{M} = \hat{r_0} - \hat{\theta} \tan{\theta} \] 1. Transform this vector into Cartesian coordinates. 2. Find the divergence of this vector in Cartesian coordinates. ### Explanations 1. **Transforming Vector into Cartesian Coordinates**: To transform \( \vec{M} \) from polar coordinates (\( \hat{r_0} \) and \( \hat{\theta} \)) to Cartesian coordinates (\( \hat{i} \) and \( \hat{j} \)), we need to use the relationships between polar and Cartesian unit vectors: - \( \hat{r_0} = \cos{\theta} \hat{i} + \sin{\theta} \hat{j} \) - \( \hat{\theta} = -\sin{\theta} \hat{i} + \cos{\theta} \hat{j} \) Substitute these into the given vector equation: \[ \vec{M} = (\cos{\theta} \hat{i} + \sin{\theta} \hat{j}) - \tan{\theta} (-\sin{\theta} \hat{i} + \cos{\theta} \hat{j}) \] Simplify this expression to get \( \vec{M} \) in terms of \( \hat{i} \) and \( \hat{j} \). 2. **Finding the Divergence**: Once \( \vec{M} \) is expressed in Cartesian coordinates, apply the divergence operator, \( \nabla \cdot \vec{M} \), which in Cartesian coordinates is: \[ \nabla \cdot \vec{M} = \frac{\partial M_x}{\partial x} + \frac{\partial M_y}{\partial y} \] where \( M_x \) and \( M_y \) are the components of \( \vec{M} \) in the \( \hat{i} \) and \( \hat{j} \) directions respectively. These steps will help in transforming the vector and then finding its divergence in Cartesian coordinates.
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