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Given that Initial Temperature = 28.5 deg C, Dew Point = 9 deg C, Dry Bulb = 30 deg C, Wet Bulb = 28 deg C, Saturation Pressure = 1.148 kPa Calculate the following: Humidity Ratio w = 0.622PsPt-Ps=0.622PsPa kg water/kg air Partial pressure of water vapour where: Ps = partial pressure of water vapour (Psat at dewpoint temperature ) w = humidity ratio Pt = total pressure (standard atmospheric pressure) Pt = Pa + Ps Pa = partial pressure of dry air = Pt - Ps 3. Relative Humidity RH = PsPd

Given that Initial Temperature = 28.5 deg C, Dew Point = 9 deg C, Dry Bulb = 30 deg C, Wet Bulb = 28 deg C, Saturation Pressure = 1.148 kPa Calculate the following: Humidity Ratio w = 0.622PsPt-Ps=0.622PsPa kg water/kg air Partial pressure of water vapour where: Ps = partial pressure of water vapour (Psat at dewpoint temperature ) w = humidity ratio Pt = total pressure (standard atmospheric pressure) Pt = Pa + Ps Pa = partial pressure of dry air = Pt - Ps 3. Relative Humidity RH = PsPd

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Given that Initial Temperature = 28.5 deg C, Dew Point = 9 deg C, Dry Bulb = 30 deg C, Wet Bulb = 28 deg C, Saturation Pressure = 1.148 kPa

Calculate the following:

  1. Humidity Ratio w = 0.622PsPt-Ps=0.622PsPa kg water/kg air
  2. Partial pressure of water vapour

where: Ps = partial pressure of water vapour (Psat at dewpoint temperature )

  w = humidity ratio

  Pt = total pressure (standard atmospheric pressure)

  Pt = Pa + Ps

  Pa = partial pressure of dry air = Pt - Ps

 

3. Relative Humidity

RH = PsPd



4. v = RaTPa   m3/kg

5. ω = 1vkg/m3

where: Pd = saturation pressure at room temperature (from steam table)

     ω = density of air

     v = specific volume of dry air 

     T = absolute temperature of room temperature 

     Ra = gas constant of air =0.28706 kJ/kg-K

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