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Given that f(x) = (x-2)/(x+3), find the slope of the tangent line at x = 2. %3D O a. 1/2 O b. -1/5 O c. 1/5 O d. -1/2 Find the derivative of y = (4 - 2x°)(2x+ x³). O a. y' = -12x5-16x3 + 12x2 + 8 O b. y = 12x5+ 16x° + 12x2 + 8 O c. y = 12x5+ 16x3 - 12x2 - 8 %3D O d. y' = -12x5+ 16x3 + 12x2 -8

Given that f(x) = (x-2)/(x+3), find the slope of the tangent line at x = 2. %3D O a. 1/2 O b. -1/5 O c. 1/5 O d. -1/2 Find the derivative of y = (4 - 2x°)(2x+ x³). O a. y' = -12x5-16x3 + 12x2 + 8 O b. y = 12x5+ 16x° + 12x2 + 8 O c. y = 12x5+ 16x3 - 12x2 - 8 %3D O d. y' = -12x5+ 16x3 + 12x2 -8

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Given that f(x) = (x-2)/(x+3), find the slope of the tangent line at x = 2. O a. 1/2 O b. -1/5 O c. 1/5 O d. -1/2 Find the derivative of y = (4 - 2x³)(2x+x³). O a. y' = -12xs-16x3 + 12x2 + 8 O b. y' = 12x5+ 16x3 + 12x² + 8 O c. y' = 12x5 + 16x3 - 12x2 - 8 O d. y' = -12x5+16x3 + 12x2 -8
Transcribed Image Text:Given that f(x) = (x-2)/(x+3), find the slope of the tangent line at x = 2. O a. 1/2 O b. -1/5 O c. 1/5 O d. -1/2 Find the derivative of y = (4 - 2x³)(2x+x³). O a. y' = -12xs-16x3 + 12x2 + 8 O b. y' = 12x5+ 16x3 + 12x² + 8 O c. y' = 12x5 + 16x3 - 12x2 - 8 O d. y' = -12x5+16x3 + 12x2 -8
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