Given that f"(x) = cos(x), f'(T/2) = 8 and f(T/2) = 6 find: || f'(x) = f(x) =

Q: If f(x) = 6 sin x + 9 cos a, then f'(x) =

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Q: Find f. f"(x) = cos(x), f(0) = 3, f'(0) = 6, f"(0) = 4

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Q: Consider the function f(x) whose second derivative is f''(x) = 3x +4 sin(a %3D If f(0) = 3 and f'(0)…

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Q: If f(x) = 3e cos(x), find f '(x) and f "(x).

A: Given,          fx=3excosx

Q: 3. Find f. (a) f"(x) = x + 12x² %3D

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Q: Let f(x)=6x/sin x + cos x f'(−π)=

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Q: Find f. f"(x) = cos(x), f(0) = 6, f'(0) = 4, f"(0) = 9 f(x) =

A: We can find the value of f(x) as below.

Q: Find f(x), where f'(x) = sin(x)+ cos(x) + 1 and f(r) = 2. %3D %3D

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Q: If f(x) = 5x(sin x + cos x), what is f'(x)?

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Q: If f(x) = (52² + lx + 6)cos(x), find f'(x) =

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Q: Find f. f(x) = f ''(x) = cos(x), f(0) = 4, f'(0) = 5, f "(0) = 7

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Q: Given f(x) = cotx 1 - csc x " then f'(x) = = 1 g(x) - 1 Find g(x).

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Q: Find the function such that f'(x)  = f(x) (1- f(x)) and  f(0)  = 1/2

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Q: Find F (x). F(x) = sin e de Jo F '(x) =

A: Given Integral: Fx=∫0x3sinθ3dθ It is required to determine the derivative of the functionF'x. The…

Q: Find f if f'''(x)=cosx,f(0)=1,f(0)=1,f'(0)=2,f''(0)=3

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Q: If f(x) = 2 sin z +9 cos z, then f'(z) = f'(4) =

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Q: If f(x) = 3 cos(5 In(x)), find f'(x). Find f'(1).

A: topic - derivatives

Q: If f(w) (3w), find f'(w). Use exact values. = COS f'(w) =

A: We can find the exact answer as below.

Q: Find g'(x) given that g(x) = x° cos(Tx) os (πα)

A: Given,  g(x)=x3cos(πx)

Q: Given the function f(x), find f'(x) f(x) = 9x² COS X

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Q: Find f'(x) and f'(c). Function Value of c sin x f(x) = f(x) =|| %3D

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Q: If f(x) = 4 cos(7 ln(x)), find f'(x). %3D Find f'(3).

A: Explanation of the answer is as follows

Q: Find g'(4) given that f(4) = -1 , f'(4) = -2 , and g(x) = Vãƒ(x).

A: Use the product rule to find the derivative of the function:

Q: If f(x) = 4x(sin a + cos x), find f'(x) = f'(5) =

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Q: If f(x) = 2 cos(3 In(x)), find f'(æ). Find f'(1).

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Q: If f(x) = 3 cos(3 In(x)), find f'(x).

A: Consider the function  f(x)=3cos3ln(x)

Q: let f(0)=0,f'(0)=2,f"(0)=3. Find g'(0) if g(x)=sin(2f(x))

A: gx=sin2fx take derivative g'x=ddxsin2fx g'x=cos2fx·ddx2fx g'x=cos2fx·2ddxfx g'x=cos2fx·2f'x