given that DTFT(0.8″ u[n]) - = 1 — 0.8eljw find the value of x[n] = 0.8"u[n − 2 = -

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given that DTFT(0.8n u[n]) =
1
1 − 0.8e−jω find the value of x[n] = 0.8nu[n − 2]

given that DTFT(0.8" u[n])
=
1 -0.8e-jw
find the value of x[n] = 0.8" u[n - 2]
Transcribed Image Text:given that DTFT(0.8" u[n]) = 1 -0.8e-jw find the value of x[n] = 0.8" u[n - 2]
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