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Given: T= Surrounding or Room Temperature%380°F T()= temperature of the body after t' hours of death To=temperature of the body at the time of death =99.9'F Tzpm=90.4°F Tspm=84.2'F Time of death is the assumed temperature on death is 96'F Temperature of the body 6pm. Solve for K- cooling Constant T(t)=T,+(To-Ts)ekt .Equation 1.3 Ts e kt=T(t)- To-Ts T(t) „T()-Ts In e-kt=In To-Ts T(t)-Ts -kt=In- To-Ts Ts k= tIn T(t) To-TS 84.2-80. k=-1/2 In 90.4-80- =1/2 In (4.2/10.4) k=0.4534

Given: T= Surrounding or Room Temperature%380°F T()= temperature of the body after t' hours of death To=temperature of the body at the time of death =99.9'F Tzpm=90.4°F Tspm=84.2'F Time of death is the assumed temperature on death is 96'F Temperature of the body 6pm. Solve for K- cooling Constant T(t)=T,+(To-Ts)ekt .Equation 1.3 Ts e kt=T(t)- To-Ts T(t) „T()-Ts In e-kt=In To-Ts T(t)-Ts -kt=In- To-Ts Ts k= tIn T(t) To-TS 84.2-80. k=-1/2 In 90.4-80- =1/2 In (4.2/10.4) k=0.4534

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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can someone explain it in detail please I can't get it 
A Time of Death To=99.9'F T4pm=84.2°FK=0.4534 84.2-80 t=-1/0.4534 In( 99.9-80 =-1/0.4534 In (4.2/19.9) =3.43 hrs or 3hrs 26 minutes t=4pm after 3hrs 26 minutes Time of death is 12:34 p.m
Transcribed Image Text:A Time of Death To=99.9'F T4pm=84.2°FK=0.4534 84.2-80 t=-1/0.4534 In( 99.9-80 =-1/0.4534 In (4.2/19.9) =3.43 hrs or 3hrs 26 minutes t=4pm after 3hrs 26 minutes Time of death is 12:34 p.m
Given: Ts= Surrounding or Room Temperature=80°F T()= temperature of the body after 't hours of death To=temperature of the body at the time of death =99.9°F Tzpm=90.4°F Tspm=84.2°F Time of death is the assumed temperature on death is 96'F Temperature of the body 6pm. Solve for K- cooling Constant T(t)=T,+(To-Ts)e*et .Equation 1.3 Ts e-kt=T(t)- To-Ts T(t) T(t)-Ts In e-kt=In- To-Ts T(t)-Ts To-Ts -kt=In Ts k=-. t In T(t) To-T's 84.2-80, k=-1/2 In 90.4-80 =1/2 In (4.2/10.4) k=0.4534
Transcribed Image Text:Given: Ts= Surrounding or Room Temperature=80°F T()= temperature of the body after 't hours of death To=temperature of the body at the time of death =99.9°F Tzpm=90.4°F Tspm=84.2°F Time of death is the assumed temperature on death is 96'F Temperature of the body 6pm. Solve for K- cooling Constant T(t)=T,+(To-Ts)e*et .Equation 1.3 Ts e-kt=T(t)- To-Ts T(t) T(t)-Ts In e-kt=In- To-Ts T(t)-Ts To-Ts -kt=In Ts k=-. t In T(t) To-T's 84.2-80, k=-1/2 In 90.4-80 =1/2 In (4.2/10.4) k=0.4534
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