Given subspaces: V3 (R) L1=<[1, 0, -1], [1, 2, 3]> L2=<[1, 0, 1], [2, -1, 0]> Find the base of space L1 ∩ L2

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Hi! Need a help with my homework. I also included a pictures of my solution, bot not sure, how am I suppose to continue. Could you please help me? And also add more explanation please, so I can better understand the topic.

Given subspaces: V3 (R)

L1=<[1, 0, -1], [1, 2, 3]>
L2=<[1, 0, 1], [2, -1, 0]>

Find the base of space L1 ∩ L2

Thank you, and have a nice day :)

Vz (R)
C,こく(7,0,-)(,,)
しzこく(70,1), (U-1,0))
し,cle
(7,0,-1) =r.(?,0,l+s(2,-2,0)
1こr.1+A.2
O=F.u+ A.(-7)
-7-r.1+ノ0
レ-トレ
ー>1f -7+20=74-7
1ニト+2イ
O = -A
ニ>A-。
ー>へニ-7
-7こト
(7,2,3)ト.(1,,)+a (L,-7)
1-ト+2っ->1t 3+2.-2)tn+3-4 -フ
2-ーの
->ノニー2
3-t+os っ>r=3
%3D
しっ4 Le
Transcribed Image Text:Vz (R) C,こく(7,0,-)(,,) しzこく(70,1), (U-1,0)) し,cle (7,0,-1) =r.(?,0,l+s(2,-2,0) 1こr.1+A.2 O=F.u+ A.(-7) -7-r.1+ノ0 レ-トレ ー>1f -7+20=74-7 1ニト+2イ O = -A ニ>A-。 ー>へニ-7 -7こト (7,2,3)ト.(1,,)+a (L,-7) 1-ト+2っ->1t 3+2.-2)tn+3-4 -フ 2-ーの ->ノニー2 3-t+os っ>r=3 %3D しっ4 Le
r+A=0aト=P ;A=-P
(1,0,)-ト(7,4-)a nei3)
1-ト4』
->74-140
○-1。コ=>A=0
1ェート+30-フ-+0=>へモー?
=> L, 7 Lz
しっnレz
しっtしe
Lと?
F.(7,0,-7)+1. (7, ?3)= 10,0,0)
21こ0
2 10
3
いめ-0y4.(-)=0
.. AND ALSO
FUR L2
き
Transcribed Image Text:r+A=0aト=P ;A=-P (1,0,)-ト(7,4-)a nei3) 1-ト4』 ->74-140 ○-1。コ=>A=0 1ェート+30-フ-+0=>へモー? => L, 7 Lz しっnレz しっtしe Lと? F.(7,0,-7)+1. (7, ?3)= 10,0,0) 21こ0 2 10 3 いめ-0y4.(-)=0 .. AND ALSO FUR L2 き
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