Given signal x(t) = 5 + sin(6t) + 2cos(8t) in MATLAB. Take t = 0:0.01:4. %3D %3D Plot Time reversal of x(t) in MATLAB.
Given signal x(t) = 5 + sin(6t) + 2cos(8t) in MATLAB. Take t = 0:0.01:4. %3D %3D Plot Time reversal of x(t) in MATLAB.
Computer Networking: A Top-Down Approach (7th Edition)
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Transcribed Image Text:**Signal Analysis and Time Reversal in MATLAB**
**Given Signal:**
The function \( x(t) = 5 + \sin(6t) + 2\cos(8t) \) needs to be generated and analyzed using MATLAB. The time vector is defined as \( t = 0:0.01:4 \).
**Objective:**
Plot the time reversal of \( x(t) \) using MATLAB.
**Steps to Follow:**
1. Define the time vector \( t \) from 0 to 4 with increments of 0.01.
2. Compute the signal \( x(t) \) using the given equation.
3. Generate the plot for the time-reversed signal, \( x(-t) \).
Use the following MATLAB code as a reference:
```matlab
% Define the time vector
t = 0:0.01:4;
% Define the signal x(t)
x_t = 5 + sin(6*t) + 2*cos(8*t);
% Time reversal
x_reversed = fliplr(x_t);
t_reversed = -fliplr(t);
% Plot the time-reversed signal
plot(t_reversed, x_reversed);
title('Time Reversal of x(t)');
xlabel('Time (t)');
ylabel('Amplitude');
grid on;
```
This script will compute and plot the time reversal of the given signal, providing insight into signal manipulation in MATLAB.
Expert Solution
Requirement:
Write a MATLAB program to plot the time-reversal signal of the signal x(t) = 5 + sin(6t) + 2cos(8t).
Given: t = 0:0.01:4
Solution:
For a signal x(t) its time-reversal signal is x(-t), i.e. multiply time by -1.
x(t) = 5 + sin(6t) + 2cos(8t)
x(-t) = 5 + sin(6*(-t)) + 2cos(8*(-t))
x(-t) = 5 - sin(6t) + 2cos(8t)
So, declare the variable t and define the function x(-t). Use the plot function to plot the x(-t).
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