Given R = 11 kΩ, solve for the output voltage Uout (in Volts). 5Ω 8V] + 10 Ω M Μ + Μ R₂ 10 Ω Μ 8 ΚΩ + Vout

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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Given \( R_x = 11 \, \text{k}\Omega \), solve for the output voltage \( v_{\text{out}} \) (in Volts).

Below is a detailed explanation of the circuit diagram:

1. **Voltage Source:**
   - There is an 8V DC voltage source connected to the circuit.

2. **Resistors:**
   - The circuit contains the following resistors:
     - \( 10 \, \Omega \) connected in series to the voltage source.
     - \( 5 \, \Omega \) connected in the feedback loop of the first operational amplifier.
     - An unknown resistor \( R_x \) given as \( 11 \, \text{k}\Omega \).
     - Another \( 10 \, \Omega \) resistor connected in parallel with \( R_x \).
     - \( 8 \, \text{k}\Omega \) connected in the feedback loop of the second operational amplifier.

3. **Operational Amplifiers:**
   - There are two operational amplifiers in the circuit:
     - The first amplifier has a \( 5 \, \Omega \) feedback resistor.
     - The second amplifier has an \( 8 \, \text{k}\Omega \) feedback resistor and produces the output voltage \( v_{\text{out}} \).

4. **Ground Connections:**
   - Each operational amplifier is connected to the ground.

Understanding the interconnectedness of these components will help in solving for \( v_{\text{out}} \).
Transcribed Image Text:Given \( R_x = 11 \, \text{k}\Omega \), solve for the output voltage \( v_{\text{out}} \) (in Volts). Below is a detailed explanation of the circuit diagram: 1. **Voltage Source:** - There is an 8V DC voltage source connected to the circuit. 2. **Resistors:** - The circuit contains the following resistors: - \( 10 \, \Omega \) connected in series to the voltage source. - \( 5 \, \Omega \) connected in the feedback loop of the first operational amplifier. - An unknown resistor \( R_x \) given as \( 11 \, \text{k}\Omega \). - Another \( 10 \, \Omega \) resistor connected in parallel with \( R_x \). - \( 8 \, \text{k}\Omega \) connected in the feedback loop of the second operational amplifier. 3. **Operational Amplifiers:** - There are two operational amplifiers in the circuit: - The first amplifier has a \( 5 \, \Omega \) feedback resistor. - The second amplifier has an \( 8 \, \text{k}\Omega \) feedback resistor and produces the output voltage \( v_{\text{out}} \). 4. **Ground Connections:** - Each operational amplifier is connected to the ground. Understanding the interconnectedness of these components will help in solving for \( v_{\text{out}} \).
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