Given P = RS?T05 + R5S sin(27) what is P !! as 0.5R ST 0.5 + 2RS cos(27") O 3R ST05 + 0.5R 04 sin(27) O2R ST05 + R 05 sin(27) O2R ST + R sin(27)
Given P = RS?T05 + R5S sin(27) what is P !! as 0.5R ST 0.5 + 2RS cos(27") O 3R ST05 + 0.5R 04 sin(27) O2R ST05 + R 05 sin(27) O2R ST + R sin(27)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Given
P = RS'T05 + R5S sin(27)
what is P
!3!
as
O0.5R s*T-05 + 2RS cos(2T)
O 3R ST05 + 0.5R 04 sin(27)
O2R ST05 + R 0 sin(27')
O2R STS + R sin(27')
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