Given Now, Let then 3 J 3 eq en of slope end P (x₁, y₁) these of Since from lipse diameter -2/3 points and will slobe 4x² + 5y² = 20 points 4x₁² + 5y2 = 20 4x²² +59₂² = २० will of chords Q (x₂, 1₂) and which be 4 (x, 2 X 2) +5 (५ - ५३) = २० - २० of уз-у, x₂-x1 4 (x₁+x1₂) 5 (Y₁+ y₂) У, -У2 11 - 32 4(x₁+x₂) 5 (Y₁+ y₂) Satisfy 4 (x²-) = 5 (9,²-²³) (५) 4(x₁-x₂)(x₁+x₂) = 5 (1₁-1₂) (Y₁ + y₂) chords = = bisects given as 11 -2/3 = with У, -У2 is X₁-42 مذاب مدان the er of ellipse -33 slope 2/3 Cords of T (5)
Given Now, Let then 3 J 3 eq en of slope end P (x₁, y₁) these of Since from lipse diameter -2/3 points and will slobe 4x² + 5y² = 20 points 4x₁² + 5y2 = 20 4x²² +59₂² = २० will of chords Q (x₂, 1₂) and which be 4 (x, 2 X 2) +5 (५ - ५३) = २० - २० of уз-у, x₂-x1 4 (x₁+x1₂) 5 (Y₁+ y₂) У, -У2 11 - 32 4(x₁+x₂) 5 (Y₁+ y₂) Satisfy 4 (x²-) = 5 (9,²-²³) (५) 4(x₁-x₂)(x₁+x₂) = 5 (1₁-1₂) (Y₁ + y₂) chords = = bisects given as 11 -2/3 = with У, -У2 is X₁-42 مذاب مدان the er of ellipse -33 slope 2/3 Cords of T (5)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
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TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT
Transcribed Image Text:Given
Now,
Let
then
IT IT T
F
en
e of
eqn
slope
Since
P (x₁, y₁)
these
end
from
Let
of
then
3
9=
ellipse
diameter
-2/3
J
points
→
slobe
en
and
4(त्र, 2 - २) +5 (५ -५२३) = २० - २०
points will
4x₁² + 5y² = 20
4x² + 5%₂2² = 20
midpoint
and
will
व
4 (x₁+x₂)
5 (Y₁+ y₂)
of
уз-у,
X₂-X₁
of
Q (x₂, 1₂)
2₁+x2
4x² + 5y² = 20
4(x7²-) = 5
У, - Уз
7₁-72
4 (2a)
5 (26)
89
lob
= 5 (y 2-93)
4(x₁-x₂)(₁+₂) = 5 (1₁-1₂) (Y₁ +1₂)
4(x₁+x₂)
5 (Y₁+ y₂)
of
which
be
4
29
5 b
3x 29
ба
chords
chords
=
Satisfy
=
=
=
--3/3
=
=
becomes
PQ
1
333
=
3
bisects
given as
3/
of diameter of ellipse
6x + 5y
у, -Уз
-3
-33
-5b
= -5 b
with
is -2
b=
X₁-12
6x = -5 y
=0
er of ellipse
the
be
slope 2/3
у, туд
Cords of
G
(9, b)
ag
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