Given mass of the block m= 1.2 kg, frictional coefficient between the block and the surface is u-0.11, a constant force f= 2.15 N acting constantly along the downward direction. [a] Use Newton's law to calculate the acceleration of the block along x. [b] Given object speed at 1-0 is 0, calculate d it moves in 5.0 s. [c]Also calculate its speed in 5.0 s.
Given mass of the block m= 1.2 kg, frictional coefficient between the block and the surface is u-0.11, a constant force f= 2.15 N acting constantly along the downward direction. [a] Use Newton's law to calculate the acceleration of the block along x. [b] Given object speed at 1-0 is 0, calculate d it moves in 5.0 s. [c]Also calculate its speed in 5.0 s.
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![QUESTION 2
Given mass of the block m= 1.2 kg, frictional coefficient between the block and the surface is u-0.11, a constant force f= 2.15 N acting constantly along
the downward direction.
[a] Use Newton's law to calculate the acceleration of the block along x.
[b] Given object speed at 1-0 is 0, calculate d it moves in 5.0 s.
[c]Also calculate its speed in 5.0 s.
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Transcribed Image Text:QUESTION 2
Given mass of the block m= 1.2 kg, frictional coefficient between the block and the surface is u-0.11, a constant force f= 2.15 N acting constantly along
the downward direction.
[a] Use Newton's law to calculate the acceleration of the block along x.
[b] Given object speed at 1-0 is 0, calculate d it moves in 5.0 s.
[c]Also calculate its speed in 5.0 s.
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