Given is the reduced prime implicant chart of a function f3(u,v,w,x,y) after the essential prime implicants have been found to be ūvy, uvỹ, uūwxy, ūūwỹ. int: mi is the dual equivalent of the minterm i, e.g. m5 = ūīwãy Prime implicant |Pa = vwy P4 = uvwy P6 = uvW Pa = ūvx |P10 = Minterm m25 m27 X m10 m14 Which of the following is a correct result of the minimized function f3,min after application of the Quine/McCluskey Algorithm to function f3? Vählen Sie eine Antwort: Oa f3.min = ūvy + uvỹ + uīwxy + ūvWxy O b. None of these c f3.mtn = ūvy + uvỹ + vwy + uūwxy + ūvx + ūīwxỹ d. f3.min = ūvy + uvỹ + vwy + uvwy + uīwxy + ūīwäy e. f3.min = ūvy + uvỹ + uūwxy + ūTWxy

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