Given integer n>0 let G ne the subset of complex numbersof the form e^((2kpii/n)i), k is an element of Z . Show that G is a group under multiplication.Howmany elements does G have?

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Given integer n>0 let G ne the subset of complex numbersof the form e^((2kpii/n)i), k is an element of Z . Show that G is a group under multiplication.Howmany elements does G have?

Expert Solution
Step 1

Note:- A set G is called Group with respect to a binary operation say · if 

1. G is closed.

2. G is associative.

3. G has an identity element.

4. G has an inverse element.

 

Given information

G is the subset of complex numbers of the form e2kπni .

Here, k,    n>0.

 

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