given input word, return the list of abbreviations. ex) word => ['word', 'wor1', 'wo1d', 'wo2', 'w1rd', 'w1r1', 'w2d', 'w3', '1ord', '1or1', '1o1d', '1o2', '2rd', '2r1', '3d', '4'] """
given input word, return the list of abbreviations. ex) word => ['word', 'wor1', 'wo1d', 'wo2', 'w1rd', 'w1r1', 'w2d', 'w3', '1ord', '1or1', '1o1d', '1o2', '2rd', '2r1', '3d', '4'] """
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
given input word, return the list of abbreviations.
ex)
word => ['word', 'wor1', 'wo1d', 'wo2', 'w1rd', 'w1r1', 'w2d', 'w3', '1ord', '1or1', '1o1d', '1o2', '2rd', '2r1', '3d', '4']
"""
def generate_abbreviations(word):
def backtrack(result, word, pos, count, cur):
if pos == len(word):
if count > 0:
cur += str(count)
result.append(cur)
return
if count > 0: # add the current word
backtrack(result, word, pos+1, 0, cur+str(count)+word[pos])
else:
backtrack(result, word, pos+1, 0, cur+word[pos])
# skip the current word
backtrack(result, word, pos+1, count+1, cur).
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