Given ∞ 5.00 6.0⁰0 0 e ,2 du = -4² e dx = 472 xe dx = 2 [0x²e = # dx = 4x2 3 [0x³²e + dx = [²x^e=4² dx = 2 I find the exact values of the following improper integrals. sqrt(3pi)/4 3/8 3sqrt3/16 9sqrt(3pi)/64 27sqrt(3pi)/128

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Given
foe
0
0
∞
-u²
е
e
du
4² dx
faze - 4²
0
xe 3 dx
2 - 4²
x² e
=
VT
dx
x¹e-¹²2 dx
=
5.00
[²0x³²e + dx = 9sqrt(3pi)/64
1° ₂
=
I
=
find the exact values of the following improper integrals.
sqrt(3pi)/4
3/8
3sqrt3/16
27sqrt(3pi)/128
Transcribed Image Text:Given foe 0 0 ∞ -u² е e du 4² dx faze - 4² 0 xe 3 dx 2 - 4² x² e = VT dx x¹e-¹²2 dx = 5.00 [²0x³²e + dx = 9sqrt(3pi)/64 1° ₂ = I = find the exact values of the following improper integrals. sqrt(3pi)/4 3/8 3sqrt3/16 27sqrt(3pi)/128
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