Given hfe = 60, hie=10000, hoe = 20μ 0, hre = 2*10^-4. Find the current gain of the BJT, correct up to two decimal points. * Vcc 15k Vo 30k 5k C3 - 60.10 - 58.44 2k Q1 10k C4 = 9 4k C2

Given hfe = 60, hie=10000, hoe = 20μ 0, hre = 210^-4. Find the current gain of the BJT, correct up to two decimal points. Vcc 15k Vo 30k 5k C3 - 60.10 - 58.44 2k Q1 10k C4 = 9 4k C2

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Electrical Heating Unit

The conversion of electrical energy to heat energy is known as electric heating. The heating system that converts the electrical energy to heat energy for various application is called electrical heating unit. Electricity is employed as the firing mechanism in electric heating systems, which transforms electric current to heat. Electric heaters have heating elements in the form of electric resistors.

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Given hfe = 60, hie=10000, hoe = 20µ Q,
hre = 2*10^-4. Find the current gain of
the BJT, correct up to two decimal points.
*
Vcc
15k
Vo
30k
5k
V1
C3
HH
- 60.10
- 58.44
- 60.00
-59.21
2k
Q1
10k
C4
G
4k
C2

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