Given f(x)= 6x –- 12 and g(x)=x – 4, find f(x)+g(x). Do not include spaces in your answer. Answer

Q: Solve for f(x)

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Q: Let f(x) = x² - 6x and g(x) = 4 - x². ▪ (f+g)(4) = (f-g) (4) = (fg)(4) = (4) (4)

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Q: Find the domain of the function g(x) =√(x - 2)/(x - 5)

A: We can not have negative number inside the square root. x-2≥0 So, x≥2

Q: show that 1f ∘ g2 (x) = 1g ∘ f2 (x) = x.

A: Given: fx=1x, gx=1x. To find: f o gx=g o fx=x Solution: Finding f o gx. f o gx=fgx=f1x=11x=x

Q: The sketch represents f(x) = x² + x – 6 and g(x) = -x – 3 P M

A: We have given functions  f(x) = x2+x-6  g(x) = -x-3 As we have given to solve for  f(x) < g(x)…

Q: consider the function f(x)=3x-1 what is f(4)

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Q: Rewrite the function f (x) = 2(x-1)-1 in the form f (x) = ax²+bx+c. f(x) = 0 %3D

A: The given function is, fx=2x-12-1 The general form is, fx=ax2+bx+c

Q: Evaluate f(x) = 8-X at x = 2. f(2) =

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Q: Find the domain of f.  f(x) = x - 4/(x - 8)(x + 8)

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Q: (f(-3))

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Q: function f(x)=(1)/(3)x-5. Identify if on. Give the domain and range.

A: Solution Here f(x)=1/(3)x-5

Q: Let f(x)=4(3)x−1. Evaluate f(3)

A: Given that, fx=43x-1 We have to evaluate f(3).