Two bugs are positioned a given distance apart. The first bug moves halfway towards the other. The second bug moves halfwayto the first. The first bug again moves halfway to the second. Compute and print the positions of the bugs.The initial position will change with each program run.// Declare position 2.../* Your code goes here */double distance = initial_distance;1112131415161718192021222324252627}// Update distance and position1distance distance * 0.5;position1= distance;cout << position1 << " " << position2 << endl;// Update distance and position2/* Your code goes here */cout << position1 << " " << position2 << endl;// Update distance and position1/* Your code goes here */cout << position1 <<return 0;"1<< position2 << endl; Given four positive integers a, b, c, and d, compute the sum of those among them that are odd.Hint: Because you have not yet learned how to make decisions, use the fact that for a positive integer n, the expression n % 2 iseither 0 or 1. You can multiply the integer n by (n % 2) to yield either zero (for even numbers) or n (for odd).1 #include 23 using namespace std;45 int main()6 {7891011121314151617int a;int b;int c;int d;cin >> a;cin >> b;cin >> c;cin >> d;* Your code goes here */

StartRead four positive integers a, b, c, and dInitialize a variable sum to 0Check if a is odd:If a…

Given four positive integers a, b, c, and d, compute the sum of those among them that are odd. Hint: Because you have not yet learned how to make decisions, use the fact that for a positive integer n, the expression n % 2 is either 0 or 1. You can multiply the integer n by (n % 2) to yield either zero (for even numbers) or n (for odd). 1 #include 2 3 4 5 int main() 6 { 7 8 9 10 11 12 13 14 using namespace std; 15 16 17 int a; int b; int c; int d; cin >> a; cin >> b; cin >> c; cin >>d; * Your code goes here */

Given four positive integers a, b, c, and d, compute the sum of those among them that are odd. Hint: Because you have not yet learned how to make decisions, use the fact that for a positive integer n, the expression n % 2 is either 0 or 1. You can multiply the integer n by (n % 2) to yield either zero (for even numbers) or n (for odd). 1 #include 2 3 4 5 int main() 6 { 7 8 9 10 11 12 13 14 using namespace std; 15 16 17 int a; int b; int c; int d; cin >> a; cin >> b; cin >> c; cin >>d; * Your code goes here */

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Variables and Constant

Constants and variables are widely used in mathematical equations and expressions. They are also commonly found in the domain of programming, where each language has its own way to differentiate between a constant and a variable. Since they have all sorts of applications, knowing their differences is a good place to start.

Question

Two bugs are positioned a given distance apart. The first bug moves halfway towards the other. The second bug moves halfway
to the first. The first bug again moves halfway to the second. Compute and print the positions of the bugs.
The initial position will change with each program run.
// Declare position 2...
/* Your code goes here */
double distance = initial_distance;
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27}
// Update distance and position1
distance distance * 0.5;
position1= distance;
cout << position1 << " " << position2 << endl;
// Update distance and position2
/* Your code goes here */
cout << position1 << " " << position2 << endl;
// Update distance and position1
/* Your code goes here */
cout << position1 <<
return 0;
"1
<< position2 << endl;

Given four positive integers a, b, c, and d, compute the sum of those among them that are odd.
Hint: Because you have not yet learned how to make decisions, use the fact that for a positive integer n, the expression n % 2 is
either 0 or 1. You can multiply the integer n by (n % 2) to yield either zero (for even numbers) or n (for odd).
1 #include <iostream>
2
3 using namespace std;
4
5 int main()
6 {
7
8
9
10
11
12
13
14
15
16
17
int a;
int b;
int c;
int d;
cin >> a;
cin >> b;
cin >> c;
cin >> d;
* Your code goes here */

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