Given f (x) = 1 – 2 cos (72) that is defined over [1,6] with a step (h) = 1. Solve points (6, 7,8, and 9) based on divided difference interpolation. • The values of A fo and Aªf1are respectively: -16, -32 O-16, -8 O-16, -64 None P1(2.5) is: O2 None -3 O-7
Given f (x) = 1 – 2 cos (72) that is defined over [1,6] with a step (h) = 1. Solve points (6, 7,8, and 9) based on divided difference interpolation. • The values of A fo and Aªf1are respectively: -16, -32 O-16, -8 O-16, -64 None P1(2.5) is: O2 None -3 O-7
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Given f (x) = 1 – 2 cos (7x) that
is defined over [1,6] with a step (h)
= 1. Solve points (6, 7,8, and 9)
based on divided difference
interpolation.
• The values of A°fo and Aªf1are
respectively:
O-16, -32
O-16, -8
O-16, -64
None
P1(2.5) is:
O2
None
O-3
O-7](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa91f5cb8-b161-47d6-971a-c08c2f90f003%2F1b7ac018-85be-474e-a95b-ec8e835def72%2F4e3nbq1_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given f (x) = 1 – 2 cos (7x) that
is defined over [1,6] with a step (h)
= 1. Solve points (6, 7,8, and 9)
based on divided difference
interpolation.
• The values of A°fo and Aªf1are
respectively:
O-16, -32
O-16, -8
O-16, -64
None
P1(2.5) is:
O2
None
O-3
O-7
Transcribed Image Text:Starting from (x=2), P3(s) at s=5 is:
None
The absolute error |P2(4) - f(4)| is:
O None
O 22
O 12
O 16
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