Given equation d² x 1 dx + dt² - t dt t- d²x dx + = t³ (x) 4 dt² dt d dt [tx] = t³ (x¹) d(tx) dt (tx) 4 t d(tx) (tx)4 1 3(tx)³ La - = t²(x) 4 = dt = fath = In t + C, C is a constant
Given equation d² x 1 dx + dt² - t dt t- d²x dx + = t³ (x) 4 dt² dt d dt [tx] = t³ (x¹) d(tx) dt (tx) 4 t d(tx) (tx)4 1 3(tx)³ La - = t²(x) 4 = dt = fath = In t + C, C is a constant
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 9T
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I got the answer with steps but I don't understand it. Could you please explain it in more detail
![Given equation
d² x
1 dx
t dt
dt²
d² x dx
t- + = t³ (x) ¹
dt² dt
+
d
dt
[tx] = t³ (x¹)
= t²(x) 4
d(tx) dt
(tx) 4 t
=
La
d(tx)
(tx)4
1
3(tx)³
=
dt
t
=
In t + C, C is a constant](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffdc321a7-0572-4d50-a9f3-8afbf4260389%2Fb9f3e465-fa5f-48bb-afe3-c8a5ff32bcb5%2Fpe32lhj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given equation
d² x
1 dx
t dt
dt²
d² x dx
t- + = t³ (x) ¹
dt² dt
+
d
dt
[tx] = t³ (x¹)
= t²(x) 4
d(tx) dt
(tx) 4 t
=
La
d(tx)
(tx)4
1
3(tx)³
=
dt
t
=
In t + C, C is a constant
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