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Given: BC 1 AD; EF 1 AD; BC = EF; B LE 2. Prove: KA= D F A 1 C E %3D 2.

Given: BC 1 AD; EF 1 AD; BC = EF; B LE 2. Prove: KA= D F A 1 C E %3D 2.

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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# Problem 2: Geometry Proof ## Diagram The image shows a geometric figure with triangle \( \triangle ABE \) and segments \( BC \) and \( EF \) intersecting segment \( AD \) at points \( F \) and \( C \) respectively. The points are labeled as follows: \( A, B, C, D, E, F \). ## Given Conditions: - \( BC \perp AD \) - \( EF \perp AD \) - \( BC \cong EF \) - \( \angle B \cong \angle E \) ## Prove: - \( \angle A \cong \angle D \) ## Flowchart Proof: The flowchart proof is not filled in. ## Two-column Proof: | **Statements** | **Reasons** | |----------------|-------------| | | | The two-column proof is not filled in. *Image rights reserved by MathBits.com.*
Transcribed Image Text:# Problem 2: Geometry Proof ## Diagram The image shows a geometric figure with triangle \( \triangle ABE \) and segments \( BC \) and \( EF \) intersecting segment \( AD \) at points \( F \) and \( C \) respectively. The points are labeled as follows: \( A, B, C, D, E, F \). ## Given Conditions: - \( BC \perp AD \) - \( EF \perp AD \) - \( BC \cong EF \) - \( \angle B \cong \angle E \) ## Prove: - \( \angle A \cong \angle D \) ## Flowchart Proof: The flowchart proof is not filled in. ## Two-column Proof: | **Statements** | **Reasons** | |----------------|-------------| | | | The two-column proof is not filled in. *Image rights reserved by MathBits.com.*
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