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Given : Ba (AW = 137.327 g/cm³) %3D FCC Atomic radius = 0.235 nm Qv = 1.23ev/atom T= 1125 °C Determine: a) Number of lattice sites, N (atoms/m3) b) Number of vacancies, Nv (atoms/m3) Number of lattice sites, (N) = %3D atoms/m3 Number of vacancies, Nv = (atoms/m3)

Given : Ba (AW = 137.327 g/cm³) %3D FCC Atomic radius = 0.235 nm Qv = 1.23ev/atom T= 1125 °C Determine: a) Number of lattice sites, N (atoms/m3) b) Number of vacancies, Nv (atoms/m3) Number of lattice sites, (N) = %3D atoms/m3 Number of vacancies, Nv = (atoms/m3)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Given : Ba (AW = 137.327 g/cm³) %3D FCC Atomic radius = 0.235 nm Qv = 1.23ev/atom T= 1125 °C Determine: a) Number of lattice sites, N (atoms/m³) b) Number of vacancies, Nv (atoms/m3) Number of lattice sites, (N) = atoms/m3 Number of vacancies, Nv = (atoms/m3)
Transcribed Image Text:Given : Ba (AW = 137.327 g/cm³) %3D FCC Atomic radius = 0.235 nm Qv = 1.23ev/atom T= 1125 °C Determine: a) Number of lattice sites, N (atoms/m³) b) Number of vacancies, Nv (atoms/m3) Number of lattice sites, (N) = atoms/m3 Number of vacancies, Nv = (atoms/m3)
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