Given are the stations and elevations of a proposed symmetrical parabolic highway curve. POINT ELEVATION (m) STATION A 93.60 6+075 B 90.00 6+255 (PI) 96.48 6+435 Note: Lines AB and BC are the tangent lines of the proposed highway curve. The curve will clear a boulder at Sta. 6+276, and the elevation of the tip of the boulder is 92.65m. Solve for the ff: a. length of the symmetrical curve b. stationing and elevation of PC

Q: Consider ?1 = -4% intersects ?2 = +3.80% at I of Chainage 52+00 with ??? = 1261.50. Design an equal…

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Q: The equation station at the PT is:

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Q: Curves Question 9 What is the degree of the curve (in degree) for a radius of 573 m using chain of…

A: Given- Radius R=573 m chain length=20 m It is needed to find the degree of the curve.

Q: What is the station of the PT of a horizontal curve with the following data: A=40°50', R=600 ft and…

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Q: Given a simple circular curve, in feet, with the following known information = 30°45'00" o Da =…

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Q: A horizontal curve is being designed with tangent length of 850 ft and central angle of 0.7315…

A: The given data is: The equation applied to determine the central angle : radius, usually measured to…

Q: 1. You are traversing along a centerline, (S 45° 00' E), at Station 1+50, you establish a BC, for a…

A: To Determine Length T1 and T2 of the given compound curve.

Q: Given the following information for a compound curve that Leads with short cur o | = 98°48'13" ols =…

A: I=98°48'13''Is=32°15'53''Ts=2110.17 feetDL=1°45' To find: Length of the long curve in feet

Q: A highway survey Pl falls in a pond, so a cut offline AB-275.21 ft is nun between the tangents. In…

A: Degree of curve = 4o30' Angle A = 16o 28' Angle B = 22o16'

Q: From the wind load design perspective, why do inclined roofs are preferred over flat roofs in…

A: Inclined roofs are preferred over flat roofs in low rise buildings because of the following reasons:

Q: A highway curve has R = 600 m, I = 20°00', and Pl station = 3 + 290.600 m. What sight distance is…

A: R = 600 mI = 20∘00′  PI station = 3 + 290.600 m.

Q: 24.9 Highway curve with Da = 5°00', I = 20°30' and PI station 63 +25.53 ft. =

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Q: Compute L, T, E, M, LC, R, and stations of the PC and PT for the highway curve with Da = 6 ∘00′,  I…

A: Highway Curve: The two lines on a roadway are connected with an arc. This connected arc of two…

Q: For the PI Inaccessible problem: Sta. X = 75+50.00, XY =800.00 ft, angle x = 35°00'00", angle y…

A: Given; Sta. X = 75+50.00 XY = 800.00 ft. angle X = 35 DEGREE angle Y = 30 DEGREE Radius for the…

Q: 24.14 Railroad curve with T 300.00 ft, D. 230', and PI station 48+ 00.00 24.13 Highway curve with T=…

A: Dc=2o30''   T=300 ft,  PI=48+00.00R=5729.6Dc=527362.5=2291.84 ftR=2291.84 ftTangent…

Q: A highway survey PI falls in a pond, so a cut off line AB= 275.21 ft is run between the tangents. In…

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Q: If you are standing at STA23+54.23, how many feet are you away from STA25+08.49 along the length of…

A: Starting Station (STA23+54.23)Ending Station (STA25+08.49)To find:The length of the alignment.

Q: Problem 2. Given are the following coordinates of stations of a simple curve: Station Northings…

A: Let T1 be the tangent between PC & PI,  and T2 be the tangent between PI & PT.

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.