Given AQRS ATUV, QS = 3v + 2 and TV = 7v – 6, find the length of QS and TV. 命 > Math symbols • Relations • Geometry » Groups ) Trigonometry » Statistics > Greek of 3 Answered O Type here to search

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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**Problem Statement:**

Given that triangles \(\triangle QRS\) and \(\triangle TUV\) are congruent, with \(QS = 3v + 2\) and \(TV = 7v - 6\), find the length of \(QS\) and \(TV\).

**Instructions:**

1. Since the triangles are congruent, their corresponding sides are equal. Thus, we have:

   \[
   QS = TV
   \]

2. Substitute the given expressions:

   \[
   3v + 2 = 7v - 6
   \]

3. Solve the equation for \(v\):

   \[
   3v + 2 = 7v - 6 
   \]
   
   Rearrange the equation:

   \[
   3v - 7v = -6 - 2 
   \]

   \[
   -4v = -8 
   \]

   Divide both sides by \(-4\):

   \[
   v = 2
   \]

4. Substitute \(v = 2\) back into one of the expressions to find the length of \(QS\) and \(TV\):

   - For \(QS\):
   
     \[
     QS = 3(2) + 2 = 6 + 2 = 8
     \]

   - For \(TV\):

     \[
     TV = 7(2) - 6 = 14 - 6 = 8
     \]

5. Therefore, the length of \(QS\) and \(TV\) is 8 units.

**Conclusion:**

Both sides \(QS\) and \(TV\) are confirmed to be equal, at a length of 8 units, which is consistent with the property of congruent triangles.
Transcribed Image Text:**Problem Statement:** Given that triangles \(\triangle QRS\) and \(\triangle TUV\) are congruent, with \(QS = 3v + 2\) and \(TV = 7v - 6\), find the length of \(QS\) and \(TV\). **Instructions:** 1. Since the triangles are congruent, their corresponding sides are equal. Thus, we have: \[ QS = TV \] 2. Substitute the given expressions: \[ 3v + 2 = 7v - 6 \] 3. Solve the equation for \(v\): \[ 3v + 2 = 7v - 6 \] Rearrange the equation: \[ 3v - 7v = -6 - 2 \] \[ -4v = -8 \] Divide both sides by \(-4\): \[ v = 2 \] 4. Substitute \(v = 2\) back into one of the expressions to find the length of \(QS\) and \(TV\): - For \(QS\): \[ QS = 3(2) + 2 = 6 + 2 = 8 \] - For \(TV\): \[ TV = 7(2) - 6 = 14 - 6 = 8 \] 5. Therefore, the length of \(QS\) and \(TV\) is 8 units. **Conclusion:** Both sides \(QS\) and \(TV\) are confirmed to be equal, at a length of 8 units, which is consistent with the property of congruent triangles.
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