Given an object thrown in the air PE and TE for the top of the trajectory, Points 1,2, 3 and bottom of the trajectory (during the trip down). NOTE: Points 1, 2, and 3 are evenly spaced distances.
Given an object thrown in the air PE and TE for the top of the trajectory, Points 1,2, 3 and bottom of the trajectory (during the trip down). NOTE: Points 1, 2, and 3 are evenly spaced distances.
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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
Transcribed Image Text:Bottom
Given an object thrown in the air vertically, indicate the values of KE,
PE and TE for the top of the trajectory, Points 1,2, 3 and bottom of the
trajectory (during the trip down).
NOTE: Points 1, 2, and 3 are evenly spaced distances.
Top
Point1
Point 2
point 3

Transcribed Image Text:Top
Point 1
Point 2
Point 3
Bottom
Law of Conservation of Energy Homework
PE = 20,000
PE =15,000
PE=
PE =5,000
PE=0
F +
KE=0 J
KE=
KE =10,000
KE=
KE =20,000
TE = 20,000
TE=20,000
TE =20,000
TE=20,000
TE=
Given an object thrown in the air vertically, indicate the values of KE,
PE and TE for the top of the trajectory, Points 1,2, 3 and bottom of the
trajectory (during the trip down).
NOTE: Points 1, 2, and 3 are evenly spaced distances
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