Given an Array M of 99 int values, and int *pit: 1. Declare two pointers pl and p2 2. Make p1 point to the first odd value in M. 3. Make p2 point to the last negative value in M.

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Given an Array M of 99 int values, and int *pit:
1. Declare two pointers p1 and p2
2. Make pl point to the first odd value in M.
3. Make p2 point to the last negative value in M.
4. Make p1 and p2 point to array locations index 15 and index 33
5. Use pointer pit to print all elements in the array in reverse.
6. Find the count elements between pl and p2 inclusive.
7. Find the product of values between pl and p2.
8. Use pointer pit to print all odd values between p1 and p2
exclusively.
9. Use pointer pit to print all values between p1 and p2 inclusive
that are odd and divisible by 5.
10. Use pit to replace all even and negative values in M with 7.
Transcribed Image Text:Given an Array M of 99 int values, and int *pit: 1. Declare two pointers p1 and p2 2. Make pl point to the first odd value in M. 3. Make p2 point to the last negative value in M. 4. Make p1 and p2 point to array locations index 15 and index 33 5. Use pointer pit to print all elements in the array in reverse. 6. Find the count elements between pl and p2 inclusive. 7. Find the product of values between pl and p2. 8. Use pointer pit to print all odd values between p1 and p2 exclusively. 9. Use pointer pit to print all values between p1 and p2 inclusive that are odd and divisible by 5. 10. Use pit to replace all even and negative values in M with 7.
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