Given a vector A = 3a, - 2a, - 16a, find its components normal to the plane 2x + 2y – z + 8 = 0 and tangential to it.

Trigonometry (MindTap Course List)
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Chapter3: Additional Topics In Trigonometry
Section: Chapter Questions
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Given a vector A =
3a, - 2a, - 16a, find its components normal to the plane
2x + 2y – z + 8 = 0 and tangential to it.
Transcribed Image Text:Given a vector A = 3a, - 2a, - 16a, find its components normal to the plane 2x + 2y – z + 8 = 0 and tangential to it.
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