Given a two dimensional array, with 20 rows and 30 columns, allocated in ANNA-- List[20][30]. Assume row-major ordering is used to store the array in memory and the address of the first array element (List[0][0]) is 0x1234. Assuming each array element occupies one word, what would be the memory address of the element List[10][21]. (Express the address in Hexadecimal.) Refer to slides 84, 85 inLecture4.pdf (“Multidimensional Array Addresses”).   Answer: Address = Starting address + [(row_num)*NUM_OF_COLUMNS + col_num]*Element_Size = 0x1234 + [10*30 + 21]*1 = 4660 + 321 = 4981 = 0x1375 I am not understanding how 4660 is calculated and the final answer

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Given a two dimensional array, with 20 rows and 30 columns, allocated in ANNA--
List[20][30]. Assume row-major ordering is used to store the array in memory and the
address of the first array element (List[0][0]) is 0x1234. Assuming each array element
occupies one word, what would be the memory address of the element List[10][21].
(Express the address in Hexadecimal.) Refer to slides 84, 85 inLecture4.pdf
(“Multidimensional Array Addresses”).

 

Answer:

Address = Starting address + [(row_num)*NUM_OF_COLUMNS +
col_num]*Element_Size
= 0x1234 + [10*30 + 21]*1 = 4660 + 321 = 4981 = 0x1375

I am not understanding how 4660 is calculated and the final answer

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