Given a two dimensional array, with 20 rows and 30 columns, allocated in ANNA-- List[20][30]. Assume row-major ordering is used to store the array in memory and the address of the first array element (List[0][0]) is 0x1234. Assuming each array element occupies one word, what would be the memory address of the element List[10][21]. (Express the address in Hexadecimal.) Refer to slides 84, 85 inLecture4.pdf (“Multidimensional Array Addresses”).   Answer: Address = Starting address + [(row_num)*NUM_OF_COLUMNS + col_num]*Element_Size = 0x1234 + [10*30 + 21]*1 = 4660 + 321 = 4981 = 0x1375 I am not understanding how 4660 is calculated and the final answer

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