Given a system with 2 memory channels and 4 DRAM DIMMs (2 DIMMs per channel), each DIMM has:• 1 rank per DIMM• 8 chips per rank• 8 bits per column• 8 banks per chip• 32,768 rows per bank• 2,048 columns per bankA) What is the total amount (bytes) of physical memory in the system?B) What is the minimum number of physical address bits needed to address this much memory?C) With the number of physical address bits obtained in 2), also assume• The physical address space has 1M (i.e., 1048576) pages (physical frames)Virtual addresses have 64 bitsWhat is the maximum number of pages in the virtual address space?

Addressing in physical and virtual memory spaces refers to the mechanism by which a computer's…

Given a system with 2 memory channels and 4 DRAM DIMMs (2 DIMMs per channel), each DIMM has: • 1 rank per DIMM • 8 chips per rank • 8 bits per column • 8 banks per chip • 32,768 rows per bank • 2,048 columns per bank A) What is the total amount (bytes) of physical memory in the system?

Given a system with 2 memory channels and 4 DRAM DIMMs (2 DIMMs per channel), each DIMM has: • 1 rank per DIMM • 8 chips per rank • 8 bits per column • 8 banks per chip • 32,768 rows per bank • 2,048 columns per bank A) What is the total amount (bytes) of physical memory in the system?

Database System Concepts

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ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

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Fundamentals of Input and Output Performance

The I/O subsystem is a component of computer system design that uses buses to assist communication between the Central Processing Unit, Computer Memory/Storage, and Input and Output Devices (that is known as peripheral devices). The I/O subsystem includes disc controllers, tape drives, discs, system buses, and other devices. The I/O database application reads and writes drives using the operating system windows I/O.

Question

Given a system with 2 memory channels and 4 DRAM DIMMs (2 DIMMs per channel), each DIMM has:
• 1 rank per DIMM
• 8 chips per rank
• 8 bits per column
• 8 banks per chip
• 32,768 rows per bank
• 2,048 columns per bank
A) What is the total amount (bytes) of physical memory in the system?
B) What is the minimum number of physical address bits needed to address this much memory?
C) With the number of physical address bits obtained in 2), also assume
• The physical address space has 1M (i.e., 1048576) pages (physical frames)
Virtual addresses have 64 bits
What is the maximum number of pages in the virtual address space?

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