Given a string s, find the first non-repeating character in it and return its index. If it does not exist, return -1. Example 1: Input: s="leetcode" Output: 0 Example 2:
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![Given a string s, find the first non-repeating character in it and return its index. If it does not exist, return -1.
Example 1:
Input: s= "leetcode"
Output: 0
Example 2:
Input: s= "loveleetcode"
Output: 2
Example 3:
Input: s= "aabb"
Output: -1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F33fc9ab2-4687-4926-ad00-a0e43e6bd4e1%2Fc5a16d6a-603f-4cd6-993b-6e719a424607%2Fjhjietv_processed.jpeg&w=3840&q=75)
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- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current stringPalindromes - “A palindrome” is a string that reads the same from both directions. For example: the word "mom" is a palindrome. Also, the string "Murder for a jar of red rum" is a palindrome. - So, you need to implement a Boolean function that takes as input a string and its return is true (1) in case the string is a palindrome and false (0) otherwise. - There are many ways to detect if a phrase is a palindrome. The method that you will implement in this task is by using two stacks. This works as follows. Push the left half of the characters to one stack (from left to right) and push the second half of the characters (from right to left) to another stack. Pop from both stacks and return false if at any time the two popped characters are different. Otherwise, you return true after comparing all the elements. Phrases of odd length have to be treated by skipping the middle element like the word "mom", your halves are "m" and "m". - Hint: (without using STL)Palindromes - “A palindrome” is a string that reads the same from both directions. For example: the word "mom" is a palindrome. Also, the string "Murder for a jar of red rum" is a palindrome. - So, you need to implement a Boolean function that takes as input a string and its return is true (1) in case the string is a palindrome and false (0) otherwise. - There are many ways to detect if a phrase is a palindrome. The method that you will implement in this task is by using two stacks. This works as follows. Push the left half of the characters to one stack (from left to right) and push the second half of the characters (from right to left) to another stack. Pop from both stacks and return false if at any time the two popped characters are different. Otherwise, you return true after comparing all the elements. Phrases of odd length have to be treated by skipping the middle element like the word "mom", your halves are "m" and "m". - Hint: (without using STL)
- Write a regular expression that defines strings that have an even (but nonzero) number of "a" characters followed by an odd number of "b" characters. For example, aab, aabbb, aaaab, and aaaabbb should all match the regular expression.public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…Write in C Language Spilitology Yosef is a peculiar fellow. He introduced the idea to study a string by splitting it into two, and he called it Splitology. Why split a string? We do not know. Didn’t we say that Yosef is a weird one? Yosef is interested in one particular type of string, a palindrome. A palindrome is a string that is the same for both forwards and backwards. Example of palindrome strings are “ada”, “taat”, and “radar”. On the other hand, string such as “taman” is not a palindrome; notice that “taman” becomes “namat” if read backwardsand it’s not the same as “taman”. As the idea of Splitology is still new, Yosef is investigating whether a string can be split into two non-empty strings such that each string is a palindrome. For example, the string “malamini” can be split into “malam” and “ini” while both of them are palindrome. Another example is “ababab”. It can be split into “aba” and “bab”, and both of them are palindrome. Note that “ababab” can also be split into…
- Target The aim of this work is to use control structures and loops. Read carefully the problem and understand what needs to be done. Read your description is given and when you understand how it works, then start designing its solution and its implementation on the computer applying the syntax and semantics of the language Java programming. Write a LongestDupSubstring.java program that accepts a string as input and compute and print the longest sub-string displayed in two times without overlap (see 5th example for overlap). If there are more from one of such sub-strings, the program displays the first one it finds as well the number of characters in the substring. If there is no substring that appears 2 times, then the program will not print anything. Execution examples (the user's input is red and the longer in length 2 substrings) 1 Example Give a string: again and again Longest substring: again Longest substring size: 5 2 Example Give a string: seven saints and seven dinners Longest…Implement the following function which accepts a string as parameter and reverses it, without using any function from the string library. void strReverse(char *str)Asap
- if strings are immutable, like in Java, we can assume that they have a static length True Falsewrite the following as a function that takes in a string and returns a string. for (int i=0; i != user_string. size(); i++){ if (islower(user_string[i])){ user_string[i]=toupper(user_string[i]); } elseif(isupper(user_string[i])){ user_string[i]=tolower(user_string[i]); } } cout<<user_string; return0; }Don't copy ASAP
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