Given a square with area of 9 square units, find the area of the regular hexagon of the same perimeter? Solution: S = 1246 = 2 apothem = 2 a = √3 area = 24 tan tan (π (1-2)) (n- (π (6-2)) san 을 + (2) (3) (6) ama = 10.3923 sq. units
Given a square with area of 9 square units, find the area of the regular hexagon of the same perimeter? Solution: S = 1246 = 2 apothem = 2 a = √3 area = 24 tan tan (π (1-2)) (n- (π (6-2)) san 을 + (2) (3) (6) ama = 10.3923 sq. units
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Please explain how to get the answer in the simplest way. Thank you
![Given a square with area of 9 square units, find
the area of the regular hexagon of the same
perimeter?
Solution: S = 1246 = 2
apothem = S
2
a
tan
area =
(π (1-2))
•//ton ( 2 (6-21)
= √3
114
san
= // (2) (3) (6)
= 10.3923
.
units](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcd5f13eb-ed8c-423c-bde9-7b5460fc42c5%2F66c4e09f-7b9f-441c-88ee-fd51410f91ba%2Funnvye7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given a square with area of 9 square units, find
the area of the regular hexagon of the same
perimeter?
Solution: S = 1246 = 2
apothem = S
2
a
tan
area =
(π (1-2))
•//ton ( 2 (6-21)
= √3
114
san
= // (2) (3) (6)
= 10.3923
.
units
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