) Given a simple circular curve with the following properties: D = 11°, bearing on coming (back) tangent is N 89°27'25" E, bearing on outgoing (forward) tangent is 50°10'05" E, the station of the PI = 22+69.77 termine: The intersection angle (H); (b) The radius (R); (c) The tangent (T); (d) The ternal distance (E); (e) The middle ordinate (M); (f) The long chord (C); (g) The gth of the curve (L); (h) Station of the PC; (i) Station of the PT nt: for formulae see below or Slides, the Reference Book or PE Civil Reference Handbook pg.
) Given a simple circular curve with the following properties: D = 11°, bearing on coming (back) tangent is N 89°27'25" E, bearing on outgoing (forward) tangent is 50°10'05" E, the station of the PI = 22+69.77 termine: The intersection angle (H); (b) The radius (R); (c) The tangent (T); (d) The ternal distance (E); (e) The middle ordinate (M); (f) The long chord (C); (g) The gth of the curve (L); (h) Station of the PC; (i) Station of the PT nt: for formulae see below or Slides, the Reference Book or PE Civil Reference Handbook pg.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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
Transcribed Image Text:**Question 1: Simple Circular Curve Calculation**
Given a simple circular curve with the following properties:
- Degree of Curve (D): 11°
- Bearing on incoming (back) tangent: N 89°27’25” E
- Bearing on outgoing (forward) tangent: S 60°10’05” E
- The station of the Point of Intersection (PI): 22+69.77
**Determine:**
(a) The intersection angle (H)
(b) The radius (R)
(c) The tangent (T)
(d) The external distance (E)
(e) The middle ordinate (M)
(f) The long chord (C)
(g) The length of the curve (L)
(h) Station of the Point of Curvature (PC)
(i) Station of the Point of Tangency (PT)
*Hint:* For formulae, refer to the slides, the reference book, or the PE Civil Reference Handbook, page 273.
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