Given a selection of n items, the number of ways to select one set of three items followed by one set of two items without replacement is n! a. 12(n-3)!(n-2)! n! b. 12(n-5)! n! с. 5(n-5)! n! d. 5(n-12)! n! е. 2(п-3)!
Given a selection of n items, the number of ways to select one set of three items followed by one set of two items without replacement is n! a. 12(n-3)!(n-2)! n! b. 12(n-5)! n! с. 5(n-5)! n! d. 5(n-12)! n! е. 2(п-3)!
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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
Transcribed Image Text:Given a selection of n items, the number of ways to select one set of three items followed
by one set of two items without replacement is
n!
а.
12(n-3)!(n-2)!
n!
b.
12(n-5)!
n!
C.
5(п-5)!
n!
d.
5(n-12)!
n!
е.
2(n-3)!
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